R(x)=x^2=2x,C(x)=10x+20

Solution for R(x)=x^2=2x,C(x)=10x+20 equation:

(R)=R^2=2R.(R)=10R+20

We move all terms to the left:

(R)-(R^2)=0

determiningTheFunctionDomain
-R^2+R=0

We add all the numbers together, and all the variables

-1R^2+R=0

a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2}
=1
$
$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2}
=0
$